السلام عليكم ورحمة الله وبركاته
أساتذتي الكرام واخوتي الطلاب
انا طالب مبتدئ في الهندسة الكهربائيه وسويت مشروع صغير ولكن صار فيه خطأ مع اني تعبت فيه وحاولت ان اجد الخطأ لكن ماقدرت اتمنى انكم تساعدوني في ايجاد الخطا وتصحيحه
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******ive:
1.To design a parallel resonant circuit which will meet the following specifications :
a. The resonant frequency fp is 50k Hz.
b. The bandwidth is 2500 HZ.
c. The max. Response is 10 V.
d. RL= 10 ohm, L = 1mH for the coil, current source has internal resistance of 40K ohm.
2. Simulate the above RLC circuit through PSPICE for frequency
Response characteristics & obtain the following:
a. The resonant freq.
b. The bandwidth.
c. The voltage Vs freq. plot.
d. The impedance Vs freq. plot.
First, find the admittance for the circuit.
Y= 1/R + ( RL / ( RL²+ω²L²) + j ( ω* C - ω * L / ( RL² + ω² L² ))
Then, put the imaginary part equal to zero to find the resonant frequency.
ω* C — ω * L / ( RL² + ω² L² ) = 0
ω* C = ω * L / ( RL² + ω² L²
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ωr = √ (1/ LC) — (RL² / L² )
solve the equation with respect to C and find value of the capacitor.
C= L /L² ωr ² + RL²
C= 0.001/(0.001)²(2П * 50,000)² + (10)²
C = 1.012* 10^(-8) F
Fide the parallel resistance using the next formula.
RP = L/RL*C = 0.001 / (10 ) (1.012* 10^(-8) )
Then, find the equivalent resistance.
Req = 40 K // 9.88 K = 7.923 K Ohm.
By using the equivalent resistance and the max. voltage ,we can find the
Current through the circuit.
I = V / R eq = 10 / 7.923 K = 1.262 m A .
Simulation:
The simulation done by using PSPICE.
Conclusion:
We designed the RLC circuit and it satisfied the given specifications , and we did the simulation for the circuit.
وشكرا لكم
المشاركة الأصلية كتبت بواسطة فهد عقل
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